Magnetic Drive Pump Sizing and Hydraulic Design Guide

Complete guide to magnetic drive pump sizing including flow-head calculations, efficiency adjustments for magnetic losses, motor selection, and NPSH verification for Equipment Engineers.

API 685HI 9.6.1

Sizing Process Overview

Magnetic drive pump sizing follows standard centrifugal pump methodology with additional considerations for magnetic coupling losses.

Sizing Steps

1. Define Process Requirements (Flow, Head, Fluid)

2. Calculate Hydraulic Power

3. Add Magnetic Coupling Losses ← Unique to Mag-Drive

4. Size Motor with Adequate Margin

5. Verify NPSH and Operating Point

6. Confirm Temperature Limits ← Unique to Mag-Drive

7. Select Final Pump Model

Process Requirements

Flow Determination

Flow TypeDefinitionHow to Determine
Rated FlowDesign operating pointProcess calculations
Normal FlowTypical day-to-day operationOperating data
Maximum FlowEnd of curve operationRunout + contingency
Minimum FlowLowest stable operationThermal/hydraulic limit

Head Calculation

ComponentFormulaNotes
Static HeadH_static = Z₂ - Z₁Elevation difference
Pressure HeadH_pressure = (P₂ - P₁) / (ρg)Vessel pressure difference
Friction HeadH_friction = f × (L/D) × (v²/2g)Pipe losses
Velocity HeadH_velocity = v²/2gUsually small
Total HeadH_total = Sum of allInclude 10-15% margin

Fluid Properties Required

PropertyUnitImpact on Sizing
Specific Gravity-Power, NPSH
ViscositycPEfficiency, head correction
Vapor PressurebaraNPSH calculation
Temperature°CMagnet selection
Solids ContentppmMust be <100 ppm for mag-drive

Hydraulic Power Calculation

Basic Hydraulic Power

P_hydraulic = (Q × H × ρ × g) / (3.6 × 10⁶)

Where:
P_hydraulic = Hydraulic power (kW)
Q = Flow rate (m³/h)
H = Total head (m)
ρ = Fluid density (kg/m³)
g = 9.81 m/s²

Simplified Formula (Water)

P_hydraulic = (Q × H) / 367

Where:
Q = Flow (m³/h)
H = Head (m)
Result in kW

Example Calculation

Given:
- Flow: 50 m³/h
- Head: 60 m
- Fluid: Water (SG = 1.0)

P_hydraulic = (50 × 60) / 367 = 8.2 kW

Shaft Power and Efficiency

Pump Shaft Power

P_shaft = P_hydraulic / η_pump

Where:
η_pump = Pump hydraulic efficiency (typically 0.60-0.80)

Efficiency Considerations

FactorTypical RangeNotes
Pump hydraulic efficiency60-80%Based on pump curve
Mechanical efficiency95-98%Bearing, seal losses
Overall pump efficiency55-75%Combined

Example

P_hydraulic = 8.2 kW
η_pump = 0.70 (from curve)

P_shaft = 8.2 / 0.70 = 11.7 kW

Magnetic Coupling Losses

Loss Components

Loss TypeSourceTypical Value
Eddy current lossesMetallic containment shell3-12% of P_shaft
Bearing frictionInner rotor in fluid2-5% of P_shaft
Magnetic slipCoupling inefficiency1-2% of P_shaft
Total magnetic lossesSum of above5-15% of P_shaft

Eddy Loss by Shell Material

Shell MaterialEddy Loss Factor
316 Stainless Steel10-15%
Hastelloy C-2768-12%
Titanium4-6%
PEEK0%
Ceramic0%

Calculating Total Magnetic Losses

P_magnetic = P_shaft × (Eddy% + Friction% + Slip%)

Example (Hastelloy shell):
P_magnetic = 11.7 × (0.10 + 0.03 + 0.02)
P_magnetic = 11.7 × 0.15 = 1.76 kW

Motor Sizing

Total Power Required

P_motor_min = P_shaft + P_magnetic

Example:
P_motor_min = 11.7 + 1.76 = 13.46 kW

Service Factor Application

StandardService FactorApplication
API 6851.15 minimumHeavy-duty service
ANSI1.0-1.15General industry
Project Standard1.15-1.25Safety margin

Motor Selection

P_motor_rated ≥ P_motor_min × Service Factor

Example:
P_motor_rated ≥ 13.46 × 1.15 = 15.5 kW

Select next standard motor: 18.5 kW

Complete Power Flow

┌─────────────────────────────────────────────────────────────┐
│                     POWER FLOW DIAGRAM                       │
├─────────────────────────────────────────────────────────────┤
│                                                              │
│  Motor Input    →   Motor Losses   →   Shaft Power          │
│  (18.5 kW)          (-1.5 kW)          (17.0 kW)           │
│                                                              │
│  Shaft Power    →   Magnetic Losses →  Available to Pump    │
│  (17.0 kW)          (-2.5 kW)          (14.5 kW)           │
│                                                              │
│  Available      →   Pump Losses     →   Hydraulic Power     │
│  (14.5 kW)          (-6.3 kW)          (8.2 kW)            │
│                                                              │
│  Overall Efficiency: 8.2/18.5 = 44%                         │
│                                                              │
└─────────────────────────────────────────────────────────────┘

NPSH Verification

NPSH Available Calculation

NPSHa = (P_suction + P_atm - P_vapor) / (ρ × g) + H_static - H_friction

Where all pressures in absolute terms

NPSH Required

SourceReliability
Vendor curveBest - specific to impeller
HI estimateGeneral guidance
Test dataMost accurate

NPSH Margin Requirements

ApplicationMinimum Margin
General serviceNPSHa ≥ NPSHr + 0.5 m
High-energy pumpsNPSHa ≥ NPSHr + 1.0 m
Critical serviceNPSHa ≥ NPSHr × 1.3

Operating Point Verification

Preferred Operating Region

ZoneFlow RangeRecommendation
Preferred80-110% BEPOptimal operation
Allowable70-120% BEPAcceptable range
Minimum StablePer vendorBelow = recirculation
MaximumEnd of curveAvoid continuous

Magnetic Pump Specific Concerns

ConcernVerification
Minimum flowHigher than conventional (15-30% BEP)
Temperature riseAt min flow, verify magnet temp OK
Decoupling torqueVerify coupling capacity at max flow

Minimum Flow Calculation

Why Higher Minimum Flow?

Magnetic pumps require higher minimum flow because:

  1. Bearing lubrication - Product-lubricated bearings need flow
  2. Magnet cooling - Heat from eddy losses must be removed
  3. Recirculation heat - Hydraulic energy converted to heat

Minimum Flow Determination

MethodFormula/Approach
Vendor dataFrom performance curve (preferred)
Rule of thumb15-30% of BEP flow
Temperature riseFlow to limit ΔT to acceptable level

Temperature Rise at Minimum Flow

ΔT = (P_shaft × η_thermal) / (Q_min × ρ × Cp)

Where:
ΔT = Temperature rise (°C)
P_shaft = Shaft power (kW)
η_thermal = % power converted to heat (~30-40%)
Q_min = Minimum flow (m³/h)
ρ = Density (kg/m³)
Cp = Specific heat (kJ/kg·°C)

Example

P_shaft = 11.7 kW
Heat fraction = 35%
Q_min = 10 m³/h = 2.78 L/s
ρ = 1000 kg/m³
Cp = 4.18 kJ/kg·°C

Heat generated = 11.7 × 0.35 = 4.1 kW = 4.1 kJ/s

ΔT = 4.1 / (2.78 × 1.0 × 4.18) = 0.35°C

(Very low because Q_min is adequate)

Recirculation Line Sizing

When Required

  • Pump may operate below minimum flow
  • Process has variable demand
  • No other flow path exists

Sizing Approach

Q_recirc = Q_min - Q_process_minimum

Where:
Q_min = Pump minimum stable flow
Q_process_minimum = Lowest expected process flow

Recirculation Options

TypeApplicationPros/Cons
Continuous orificeSimple, low costWastes energy
ARC valveAutomatic controlMore complex
Control valvePrecise controlExpensive
Flow switch + valveOn/off protectionSimple

Torque and Coupling Verification

Magnetic Coupling Torque

T_required = (P_shaft × 9550) / n

Where:
T_required = Torque (Nm)
P_shaft = Shaft power (kW)
n = Speed (rpm)

Torque Margin

ConditionRequired Margin
Normal operation1.5× required torque
Startup (cold)2.0× required torque
Viscous fluids2.5× required torque

Decoupling Prevention

T_coupling > T_max_load × SF

Where SF = 1.5 minimum per API 685

Summary Sizing Checklist

=== MAGNETIC PUMP SIZING CHECKLIST ===

□ Process Requirements
  □ Flow: Rated ___ m³/h, Min ___ m³/h, Max ___ m³/h
  □ Head: ___ m (includes margins)
  □ Fluid: ___ (SG: ___, Viscosity: ___ cP)
  □ Temperature: ___ °C normal, ___ °C max

□ Hydraulic Calculations
  □ P_hydraulic = ___ kW
  □ P_shaft = ___ kW (at η_pump = ___%)

□ Magnetic Losses
  □ Shell material: ___________
  □ Eddy losses: ___ kW (___%)
  □ Friction losses: ___ kW (___%)
  □ Total magnetic: ___ kW (___%)

□ Motor Selection
  □ P_minimum = P_shaft + P_magnetic = ___ kW
  □ Service factor: ___
  □ P_motor selected: ___ kW

□ NPSH Verification
  □ NPSHa = ___ m
  □ NPSHr = ___ m
  □ Margin = ___ m (≥ 0.5m? □)

□ Operating Point
  □ Duty point at ___% of BEP (70-120%? □)
  □ Minimum flow = ___ m³/h
  □ Recirculation required? □ Yes □ No

□ Temperature Verification
  □ Process temp: ___ °C
  □ + Eddy heating: ___ °C
  □ + Safety margin: ___ °C
  □ Total: ___ °C < Magnet MAT? □

□ Coupling Verification
  □ Required torque: ___ Nm
  □ Coupling rating: ___ Nm
  □ Margin: ___ (≥ 1.5? □)

Quick Reference Formulas

ParameterFormulaUnits
Hydraulic PowerQ × H × SG / 367kW
Shaft PowerP_hyd / η_pumpkW
Total Motor PowerP_shaft × (1 + magnetic loss%)kW
TorqueP × 9550 / nNm
Temp RiseP × η_heat / (Q × ρ × Cp)°C
NPSH marginNPSHa - NPSHrm

Frequently Asked Questions

How do magnetic losses affect pump sizing?
Magnetic coupling losses (5-15% of shaft power) must be added when sizing the motor. A pump requiring 10 kW shaft power with 10% magnetic loss needs a motor rated for at least 11.5-12 kW to ensure adequate power margin.
What is minimum flow for magnetic pumps?
Minimum flow is typically 15-30% of BEP flow, higher than conventional pumps. This ensures adequate cooling flow through the magnetic coupling area and proper bearing lubrication. Operating below minimum flow causes rapid bearing wear and magnet overheating.
How do I calculate total power requirement?
Total power = Hydraulic power ÷ Pump efficiency + Magnetic losses + Safety factor. Include eddy current losses from metallic containment shells and bearing friction losses in the magnetic coupling area.

📚 References & Sources

Need Help Evaluating Vendor Proposals?

AutoTBE uses AI to analyze technical bids and generate comprehensive comparison reports in minutes.

Try AutoTBE Free